Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter 1 - Equations and Inequalities - Chapter 1 Test Prep - Review Exercises - Page 178: 36

Answer

$-i$

Work Step by Step

$\dfrac {1}{i^{17}}=\dfrac {i}{i^{18}}=\dfrac {i}{i^{16}\times i^{2}}=\dfrac {i}{1\times i^{2}}=\dfrac {i}{-1}=-i$
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