#### Answer

$-i$

#### Work Step by Step

$\dfrac {1}{i^{17}}=\dfrac {i}{i^{18}}=\dfrac {i}{i^{16}\times i^{2}}=\dfrac {i}{1\times i^{2}}=\dfrac {i}{-1}=-i$

Published by
Pearson

ISBN 10:
013421742X

ISBN 13:
978-0-13421-742-0

$-i$

You can help us out by revising, improving and updating this answer.

Update this answerAfter you claim an answer you’ll have **24 hours** to send in a draft. An editor
will review the submission and either publish your submission or provide feedback.