Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter 1 - Equations and Inequalities - Chapter 1 Test Prep - Review Exercises - Page 178: 30



Work Step by Step

$\dfrac {-7+i}{-1-i}=\dfrac {7-i}{1+i}=\dfrac {\left( 7-i\right) \left( 1-i\right) }{\left( 1+i\right) \left( 1-i\right) }=\dfrac {7-7i-i+i^{2}}{1-i^{2}}=\dfrac {7-8i+i^{2}}{1-i^{2}}=\dfrac {7-8i+\left( -1\right) }{1-\left( -1\right) }=\dfrac {6-8i}{2}=3-4i$
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