Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter 1 - Equations and Inequalities - Chapter 1 Test Prep - Review Exercises - Page 178: 39

Answer

$-6;5$

Work Step by Step

$2x^{2}+x-15=0\Rightarrow x_{1,2}=\dfrac {-b\pm \sqrt {b^{2}-4ac}}{2a}=\dfrac {-1\pm \sqrt {1-4\times 2\times \left( -15\right) }}{2\times 2}=\dfrac {-1\pm 11}{2}=-6;5$
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