Answer
$-6;5$
Work Step by Step
$2x^{2}+x-15=0\Rightarrow x_{1,2}=\dfrac {-b\pm \sqrt {b^{2}-4ac}}{2a}=\dfrac {-1\pm \sqrt {1-4\times 2\times \left( -15\right) }}{2\times 2}=\dfrac {-1\pm 11}{2}=-6;5$
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