#### Answer

$=1-2i$

#### Work Step by Step

$\dfrac {-12-i}{-2-5i}=\dfrac {12+i}{2+5i}=\dfrac {\left( 12+i\right) \left( 2-5i\right) }{\left( 2+5i\right) \left( 2-5i\right) }=\dfrac {24-60i+2i-5i^{2}}{4-25i^{2}}=\dfrac {24-58i-5\times \left( -1\right) }{4-25\times \left( -1\right) }=\dfrac {29-58i}{29}=1-2i$