#### Answer

$-1$

#### Work Step by Step

$i^{110}=i^{108}\times i^{2}=\left( i^{4}\right) ^{27}xi^{2}=1^{27}\times \left( -1\right) =-1$

Published by
Pearson

ISBN 10:
013421742X

ISBN 13:
978-0-13421-742-0

$-1$

$i^{110}=i^{108}\times i^{2}=\left( i^{4}\right) ^{27}xi^{2}=1^{27}\times \left( -1\right) =-1$

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