Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter 1 - Equations and Inequalities - Chapter 1 Test Prep - Review Exercises - Page 178: 40


$x_{1}=\dfrac {1}{6};x_{2}=\dfrac {1}{2}$

Work Step by Step

$12x^{2}=8x-1\Rightarrow 12x^{2}-8x+1=0\Rightarrow \left( 6x-1\right) \left( 2x-1\right) =0\Rightarrow x_{1}=\dfrac {1}{6};x_{2}=\dfrac {1}{2}$
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