Answer
$x_{1}=\dfrac {1}{6};x_{2}=\dfrac {1}{2}$
Work Step by Step
$12x^{2}=8x-1\Rightarrow 12x^{2}-8x+1=0\Rightarrow \left( 6x-1\right) \left( 2x-1\right) =0\Rightarrow x_{1}=\dfrac {1}{6};x_{2}=\dfrac {1}{2}$
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