Answer
$\color{blue}{-32+36i}$
Work Step by Step
$4i(2+5i)(2-i)$
$4i(4-2i+10i-5i^2)$
$4i(4+8i-5(-1))$
$4i(4+8i+5)$
$4i(8i+9)$
$32i^2+36i$
$32(-1)+36i$
$\color{blue}{-32+36i}$
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