Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter 1 - Equations and Inequalities - 1.7 Inequalities - 1.7 Exercises - Page 159: 35


$\color{blue}{[-9, 9]}$

Work Step by Step

Multiply $2$ to each part: \begin{array}{ccccc} &2(-4)&\le &2 \cdot \dfrac{x+1}{2} &\le &2(5) \\&-8 &\le &x+1 &\le &10 \end{array} Subtract $1$ to each part: \begin{array}{ccccc} \\&-8-1 &\le &x+1-1 &\le &10-1 \\&-9 &\le &x &\le &9 \end{array} Thus, the solution to the given inequality is: $\color{blue}{[-9, 9]}$
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