Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter 1 - Equations and Inequalities - 1.7 Inequalities - 1.7 Exercises - Page 159: 19


$\color{blue}{(-\infty, 4)}$

Work Step by Step

Distribute $2$ to obtain: $8x-3x+2 \lt 2(x)+2(7) \\5x+2 \lt 2x+14$ Subtract $2x$ and $2$ to both sides, then combine like terms to obtain: $5x+2-2-2x\lt 2x+14-2-2x \\3x \lt 12$ Divide $4$ to both sides of thee equation to obtain: $\dfrac{3x}{3} \lt \dfrac{12}{3} \\x \lt 4$ Thus , the solution set is: $\color{blue}{(-\infty, 4)}$
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