#### Answer

$\color{blue}{[-1 , +\infty)}$

#### Work Step by Step

Add $2$ and subtract $x$ to both sides, then combine like terms to obtain:
$-2x-2+2 -x\le 1+x+2-x
\\-3x \le 3$
Divide $-3$ to both sides.
Since a negative number was divided to both sides of the inequality, the inequality symbol will be reversed.
$\dfrac{-3x}{-3} \ge \dfrac{3}{-3}
\\x \ge -1$
In interval notation, the solution set is:
$\color{blue}{[-1 , +\infty)}$