Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter 1 - Equations and Inequalities - 1.7 Inequalities - 1.7 Exercises - Page 159: 15


$\color{blue}{[-1 , +\infty)}$

Work Step by Step

Add $2$ and subtract $x$ to both sides, then combine like terms to obtain: $-2x-2+2 -x\le 1+x+2-x \\-3x \le 3$ Divide $-3$ to both sides. Since a negative number was divided to both sides of the inequality, the inequality symbol will be reversed. $\dfrac{-3x}{-3} \ge \dfrac{3}{-3} \\x \ge -1$ In interval notation, the solution set is: $\color{blue}{[-1 , +\infty)}$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.