Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter 1 - Equations and Inequalities - 1.7 Inequalities - 1.7 Exercises - Page 159: 31


$\color{blue}{3 \le x \le 6}$

Work Step by Step

Subtract $4$ to each part: \begin{array}{ccccc} &10-4 &\le &2x+4-4 &\le &16-4 \\&6 &\le &2x &\le &12 \end{array} Divide each part by $2$: \begin{array}{ccccc} \\&\frac{6}{2} &\lt &\frac{2x}{2} &\lt &\frac{12}{2} \\&3 &\lt &x &\lt &6 \end{array} Thus, the solution to the given inequality is: $\color{blue}{3 \le x \le 6}$
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