Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter 1 - Equations and Inequalities - 1.7 Inequalities - 1.7 Exercises - Page 159: 32

Answer

$\color{blue}{-1.5 \le x \le 3}$

Work Step by Step

Subtract $3$ to each part: \begin{array}{ccccc} &-6-3 &\le &6x+3-3 &\le &21-3 \\&-9 &\le &6x &\le &18 \end{array} Divide each part by $6$: \begin{array}{ccccc} \\&\frac{-9}{6} &\le &\frac{6x}{6} &\le &\frac{18}{6} \\&-1.5 &\le &x &\le &3 \end{array} Thus, the solution to the given inequality is: $\color{blue}{-1.5 \le x \le 3}$
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