Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter 1 - Equations and Inequalities - 1.7 Inequalities - 1.7 Exercises - Page 159: 30

Answer

$\color{blue}{(-3,1)}$

Work Step by Step

Subtract $2$ to each part: \begin{array}{ccccc} &-7-2 &\lt &2+3x-2 &\lt &5-2 \\&-9 &\lt &3x &\lt &3 \end{array} Divide each part by $3$: \begin{array}{ccccc} \\&\frac{-9}{3} &\lt &\frac{3x}{3} &\lt &\frac{3}{3} \\&-3 &\lt &x &\lt &1 \end{array} Thus, the solution to the given inequality in interval notation is $\color{blue}{(-3,1)}$
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