#### Answer

$\color{blue}{(-\infty, 1]}$

#### Work Step by Step

Subtract $3$ and $x$ to both sides, then combine like terms to obtain:
$-4x+3-3-x\ge -2+x-3-x
\\-5x \ge -5$
Divide $-5$ to both sides.
Since a negative number was divided to both sides of the inequality, the inequality symbol will be reversed.
$\dfrac{-5x}{-5} \le \dfrac{-5}{-5}
\\x \le 1$
In interval notation, the solution set is:
$\color{blue}{(-\infty, 1]}$