## Precalculus (6th Edition)

$\color{blue}{(-\infty, 1]}$
Subtract $3$ and $x$ to both sides, then combine like terms to obtain: $-4x+3-3-x\ge -2+x-3-x \\-5x \ge -5$ Divide $-5$ to both sides. Since a negative number was divided to both sides of the inequality, the inequality symbol will be reversed. $\dfrac{-5x}{-5} \le \dfrac{-5}{-5} \\x \le 1$ In interval notation, the solution set is: $\color{blue}{(-\infty, 1]}$