Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter 1 - Equations and Inequalities - 1.7 Inequalities - 1.7 Exercises - Page 159: 33


$\color{blue}{(4, 6)}$

Work Step by Step

Subtract $1$ to each part: \begin{array}{ccccc} &-11-1 &\gt &-3x+1-1 &\gt &-17-1 \\&-12 &\gt &-3x &\gt &-18 \end{array} Divide each part by $-3$. Note that since a negative number is divided to the inequality, the inequality symbol will be reversed. \begin{array}{ccccc} \\&\frac{-12}{-3} &\lt &\frac{-3x}{-3} &\lt &\frac{-18}{-3} \\&4 &\lt &x &\lt &6 \end{array} Thus, the solution to the given inequality is: $\color{blue}{(4, 6)}$
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