Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter 1 - Equations and Inequalities - 1.7 Inequalities - 1.7 Exercises - Page 159: 13


$\color{blue}{[-4 , +\infty)}$

Work Step by Step

Subtract $8$ to both sides: $-2x+8-8 \le 16-8 \\-2x \le 8$ Divide $-2$ to both sides. Since a negative number was divided to both sides of the inequality, the inequality symbol will be reversed. $\dfrac{-2x}{-2} \ge \dfrac{8}{-2} \\x \ge -4$ In interval notation, the solution set is: $\color{blue}{[-4 , +\infty)}$
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