Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter P - Section P.5 - Factoring Polynomials - Exercise Set: 83

Answer

$5y^2(2y+3)(2y-3)$

Work Step by Step

$20y^4 - 45y^2$ factor out GCF... $5y^2(4y^2-9)$ Recall that $a^2−b^2=(a+b)(a−b)$. We use this to simplify the expression: $5y^2(4y^2-9)=5y^2(2y+3)(2y-3)$
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