Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter P - Section P.5 - Factoring Polynomials - Exercise Set: 58

Answer

$(x+4)(x^2-4x+16)$

Work Step by Step

The given expression can be written as $x^3+4^3.$ RECALL: $a^3+b^3=(a+b)(a^2-ab+b^2).$ Factor the given sum of two cubes to obtain $(x+4)(x^2-x(4)+4^2) \\=(x+4)(x^2-4x+16).$
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