## Precalculus (6th Edition) Blitzer

Published by Pearson

# Chapter P - Section P.5 - Factoring Polynomials - Exercise Set: 60

#### Answer

$(x-3)(x^2+3x+9)$

#### Work Step by Step

RECALL: A difference of two cubes can be factored using the formula: $a^3-b^3 = (a-b)(a^2+ab+b^2)$ The given expression can be written as: $x^3-3^3$ The binomial above is a difference of two cubes. Factor using the formula above with $a=x$ and $b=3$ to obtain: $=(x-3)(x^2+x(3) + 3^2) \\=(x-3)(x^2+3x+9)$

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