Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter P - Section P.5 - Factoring Polynomials - Exercise Set: 84

Answer

$3y^2(4y+1)(4y-1)$

Work Step by Step

$ 48y^4 - 3y^2$ factor out GCF... $3y^2(16y^2-1)$ Recall that $a^2−b^2=(a+b)(a−b)$. We use this to simplify the expression: $3y^2(16y^2-1)=3y^2(4y+1)(4y-1)$.
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