Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter P - Section P.5 - Factoring Polynomials - Exercise Set - Page 69: 118


$a.\quad 49x^{2}-36$ $ b.\quad (7x+6)(7x-6)$

Work Step by Step

$a.$ From the square with side of length $7x$, subtract 4 squares with sides of length $3$. $(7x)^{2}-4\cdot 3^{2}=49x^{2}-36$ $b.$ $49x^{2}-36$= ... a difference of squares, $(7x)^{2}-(6)^{2}$ $=(7x+6)(7x-6)$
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