Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter P - Section P.5 - Factoring Polynomials - Exercise Set: 74

Answer

$6(x-2)(x+1)$

Work Step by Step

Factor out $6$ to obtain: $=6(x^2-x-2)$ The leading coefficient of the trinomial is 1. Factor the trinomial by looking for the factors of the constant term $(-2)$ whose sum is equal to the coefficient of the middle term $(-1)$. Note that $-2=-2(1)$ and $-2+1 = -1$. Thus, the factors we are looking for are $-2$ and $1$. This means that the factors of the trinomial are: $x-2$ and $x+1$ Therefore the completely factored form of the given polynomial is: $=6(x-2)(x+1)$
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