Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter P - Section P.5 - Factoring Polynomials - Exercise Set: 59

Answer

$(x-4)(x^2+4x+16)$

Work Step by Step

RECALL: A difference of two cubes can be factored using the formula: $a^3-b^3 = (a-b)(a^2+ab+b^2)$ The given expression can be written as: $x^3-4^3$ The binomial above is a difference of two cubes. Factor using the formula above with $a=x$ and $b=4$ to obtain: $=(x-4)(x^2+x(4) + 4^2) \\=(x-4)(x^2+4x+16)$
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