Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter P - Section P.5 - Factoring Polynomials - Exercise Set: 68

Answer

$6(x-5)(x+2)$

Work Step by Step

Factor out the GCF of $6$ to obtain: $=6(x^2-3x-10)$ The leading coefficient of the trinomial is 1. Factor the trinomial by looking for factors of the constant term $(-10)$ whose sum is equal to the coefficient of the middle term $(-3)$. Note that $-10=-5(2)$ and $-5+2=-3$. This means that the factors we are looking for are $-5$ and $2$, and that the factored form of the trinomial is $(x-5)(x+2)$. Thus, the completely factored form of the given polynomial is: $=6(x-5)(x+2)$
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