Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter P - Review Exercises - Page 142: 7

Answer

$C\cap A=\{a\}$

Work Step by Step

Recall that an element $x\in C\cap A$ if and only if $x\in C$ and $x\in A$. Thus, we find the intersection by finding the elements that are contained in both set $A$ and set $C$. This gives us $C\cap A=\{a\}$.
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