## Precalculus (6th Edition) Blitzer

$C\cap A=\{a\}$
Recall that an element $x\in C\cap A$ if and only if $x\in C$ and $x\in A$. Thus, we find the intersection by finding the elements that are contained in both set $A$ and set $C$. This gives us $C\cap A=\{a\}$.