Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter P - Review Exercises: 29

Answer

$10x^{-8}$

Work Step by Step

$(-5x^3y^2)(-2x^{-11}y^{-2})=(-5)(-2)(x^3)(x^{-11})(y^2)(y^{-2})=10x^{3-11}y^{2-2}=10x^{-8}$
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