Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter P - Review Exercises: 28

Answer

$-8x^{12}y^{9}$

Work Step by Step

$(-2x^{4}y^{3})^3=(-2x^{4}y^{3})(-2x^{4}y^{3})(-2x^{4}y^{3})=(-2)(-2)(-2)(x^4)(x^4)(x^4)(y^{3})(y^{3})(y^{3})=-8x^{4+4+4}y^{3+3+3}=-8x^{12}y^{9}$
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