Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter P - Review Exercises - Page 142: 28

Answer

$-8x^{12}y^{9}$

Work Step by Step

$(-2x^{4}y^{3})^3=(-2x^{4}y^{3})(-2x^{4}y^{3})(-2x^{4}y^{3})=(-2)(-2)(-2)(x^4)(x^4)(x^4)(y^{3})(y^{3})(y^{3})=-8x^{4+4+4}y^{3+3+3}=-8x^{12}y^{9}$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.