## Precalculus (6th Edition) Blitzer

$.023$
$\frac{6.9\times10^3}{3\times10^5}=\frac{6.9}{3}\times\frac{10^3}{10^5}=2.3\times10^{-2}$ Since we're multiplying $2.3$ by $10^{-2}$, we move the decimal place over two spaces to the left, giving us $.023$.