Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter P - Review Exercises - Page 142: 37



Work Step by Step

$\frac{6.9\times10^3}{3\times10^5}=\frac{6.9}{3}\times\frac{10^3}{10^5}=2.3\times10^{-2}$ Since we're multiplying $2.3$ by $10^{-2}$, we move the decimal place over two spaces to the left, giving us $.023$.
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