Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter P - Review Exercises - Page 142: 36



Work Step by Step

$(3\times10^3)(1.3\times10^2)=3\times1.3\times10^3\times10^2=3.9\times10^5$ Since we're multiplying $3.9$ by $10^5$, we move the decimal place five digits to the right, giving us $390,000$.
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