Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter P - Review Exercises: 31

Answer

$\frac{1}{4}x^{-10}y^8$

Work Step by Step

$\frac{7x^5y^6}{28x^{15}y^{-2}}=\frac{7}{28}*\frac{x^5}{x^{15}}*\frac{y^6}{y^{-2}}=\frac{1}{4}x^{5-15}y^{6--2}=\frac{1}{4}x^{-10}y^8$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.