## Precalculus (6th Edition) Blitzer

Published by Pearson

# Chapter P - Review Exercises: 27

#### Answer

$\frac{1}{27}$

#### Work Step by Step

Expand the exponents in the numerator and denominator, and simplify: $$\frac{3^3}{3^6}=\frac{3\cdot 3\cdot 3}{3\cdot 3\cdot 3\cdot3\cdot 3\cdot 3}=\frac{1}{3\cdot 3\cdot 3}=\frac{1}{27}$$

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.