Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter P - Review Exercises - Page 142: 42

Answer

$2x\sqrt 3$

Work Step by Step

$\sqrt {12x^2}=\sqrt {12}\times\sqrt {x^2}=\sqrt {4\times3}\times\sqrt {x^2}=\sqrt 4\times\sqrt 3\times x=2\times\sqrt 3\times x= 2x\sqrt 3$
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