Answer
$\frac{x^2}{25}+\frac{y^2}{9}=1$
Work Step by Step
Step 1. With the given conditions, we have $c=4, a=5$; thus $b^2=5^2-4^2=9$
Step 2. The center is at $(0,0)$, so we can write the equation as $\frac{x^2}{25}+\frac{y^2}{9}=1$
Precalculus (6th Edition) Blitzer
by Blitzer, Robert F.
Published by
Pearson
ISBN 10:
0-13446-914-3
ISBN 13:
978-0-13446-914-0
Chapter 9 - Review Exercises - Page 1035: 9
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