Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 9 - Review Exercises - Page 1035: 9



Work Step by Step

Step 1. With the given conditions, we have $c=4, a=5$; thus $b^2=5^2-4^2=9$ Step 2. The center is at $(0,0)$, so we can write the equation as $\frac{x^2}{25}+\frac{y^2}{9}=1$
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