Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 9 - Review Exercises - Page 1035: 13


Yes, see explanations.

Work Step by Step

Step 1. With the given conditions, we have $b=15\ ft, 2a=50, a=25\ ft$, Step 2. The center is at $(0,0)$, we can write the equation as $\frac{x^2}{625}+\frac{y^2}{225}=1$ Step 3. The width of the truck gives $x=14\ ft$; plug-in the equation and we have $\frac{14^2}{625}+\frac{y^2}{225}=1$, which gives $y\approx12.4\ ft$ Step 4. The height of the truck is $12 \lt 12.4\ ft $; this means that the truck can pass under the archway without going into the other lane.
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