Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 9 - Review Exercises - Page 1035: 11



Work Step by Step

Step 1. With the given conditions, we have $2a=12, a=6$, and $2b=4, b=2$ Step 2. The center is at $(-3,5)$, so we can write the equation as $\frac{(x+3)^2}{36}+\frac{(y-5)^2}{4}=1$
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