Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 9 - Review Exercises - Page 1035: 24



Work Step by Step

Step 1. From the given conditions, we have $c=8, a=3$; thus $b=\sqrt {8^2-3^2}=\sqrt {55}$ with center at $(0,0)$ and foci on $y=0$ Step 2. We can write the equation as $\frac{x^2}{9}-\frac{y^2}{55}=1$
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