Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 9 - Review Exercises - Page 1035: 8

Answer

See graph and explanations.
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Work Step by Step

Step 1. Rewrite the equation as $9(x^2-2x+1)+4(y^2+2y+1)=9+4+23$ or $\frac{(x-1)^2}{4}+\frac{(y+1)^2}{9}=1$ We can identify $a=3, b=2, c=\sqrt {9-4}=\sqrt 5$ with a center at $(1,-1)$ Step 2. See graph; we can locate the foci at $(1,-1\pm\sqrt 5)$
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