Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 9 - Review Exercises - Page 1035: 12

Answer

$\frac{x^2}{100}+\frac{y^2}{36}=1$

Work Step by Step

Step 1. With the given conditions, we have $2a=20, a=10\ yd$ (horizontal), and $b=6\ yd$ Step 2. The center is at $(0,0)$, so we can write the equation as $\frac{x^2}{100}+\frac{y^2}{36}=1$
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