Answer
See graph and explanations.
Work Step by Step
Step 1. Rewrite the equation as
$\frac{x^2}{4}+\frac{y^2}{16}=1$
We have
$a=4, b=2, c=\sqrt {16-4}=2\sqrt {3}$
Step 2. See graph; we can locate the foci at $(0,\pm2\sqrt {3})$
Precalculus (6th Edition) Blitzer
by Blitzer, Robert F.
Published by
Pearson
ISBN 10:
0-13446-914-3
ISBN 13:
978-0-13446-914-0
Chapter 9 - Review Exercises - Page 1035: 3
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