Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 9 - Review Exercises - Page 1035: 4

Answer

See graph and explanations.

Work Step by Step

Step 1. Rewrite the equation as $\frac{x^2}{9}+\frac{y^2}{4}=1$ We have $a=3, b=2, c=\sqrt {9-4}=\sqrt {5}$ Step 2. See graph; we can locate the foci at $(\pm\sqrt {5},0)$
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