## Precalculus (6th Edition) Blitzer

The solution of the system of equations is $\left( x,y \right)=\left( \frac{1}{2a},\frac{1}{b} \right)$.
$4ax+by=3$ (I) $6ax+5by=8$ (II) Now, multiply equation (I) by −5 to obtain; $-20ax-5by=-15$ (III) And add equations (II) and (III): \begin{align} & 6ax+5by-20ax-5by=8-15 \\ & -14ax=-7 \\ & x=\frac{1}{2a} \end{align} Substitute the value of x in the equation (I): \begin{align} & 2+by=3 \\ & by=1 \\ & y=\frac{1}{b} \end{align} Thus, the solution set the system of equations is $\left( x,y \right)=\left( \frac{1}{2a},\frac{1}{b} \right)$.