Answer
The required value is $\left\{ \left( 3,-2 \right) \right\}$
Work Step by Step
We have to multiply the second equation by $5$ and add this to the first equation:
$\begin{align}
& 2x+5y+5\left( 3x-y \right)=-4+5\left( 11 \right) \\
& 2x+5y+15x-5y=-4+55 \\
& 17x=51 \\
& x=3
\end{align}$
Substitute the value of $x$ in the first equation to obtain,
$\begin{align}
& 6+5y=-4 \\
& 5y=-10 \\
& y=-2
\end{align}$.
Thus, the solution set is $\left\{ \left( 3,-2 \right) \right\}$.
