Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 7 - Section 7.1 - Systems of Linear Equations in Two Variables - Exercise Set - Page 818: 36


The required value is $\left\{ \left( 3,-2 \right) \right\}$

Work Step by Step

We have to multiply the second equation by $5$ and add this to the first equation: $\begin{align} & 2x+5y+5\left( 3x-y \right)=-4+5\left( 11 \right) \\ & 2x+5y+15x-5y=-4+55 \\ & 17x=51 \\ & x=3 \end{align}$ Substitute the value of $x$ in the first equation to obtain, $\begin{align} & 6+5y=-4 \\ & 5y=-10 \\ & y=-2 \end{align}$. Thus, the solution set is $\left\{ \left( 3,-2 \right) \right\}$.
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