Answer
$(-1,-2)$
Work Step by Step
Here, we have $2x=3y+4 \implies x=\dfrac{3y+4}{2}$
Now, $2(\dfrac{3y+4}{2})+6y=5y-4$
This gives: $4y=-8$ or, $y=-2$
Thus, $y=\dfrac{3(-2)+4}{2}=-1$
Solution is: $(x,y)=(-1,-2)$
Precalculus (6th Edition) Blitzer
by Blitzer, Robert F.
Published by
Pearson
ISBN 10:
0-13446-914-3
ISBN 13:
978-0-13446-914-0
Chapter 7 - Section 7.1 - Systems of Linear Equations in Two Variables - Exercise Set - Page 818: 16
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