Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 7 - Section 7.1 - Systems of Linear Equations in Two Variables - Exercise Set - Page 818: 14



Work Step by Step

Here, we have $6y=8+x \implies x=6y-8$ Now, $2(6y-8)+5y=1$ This gives: $12y-16+5y=1 $ or, $y=1$ Thus, $x=6(1)-8=-2$ Solution is: $(x,y)=(-2,1)$
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