## Precalculus (6th Edition) Blitzer

$(-2,1)$
Here, we have $6y=8+x \implies x=6y-8$ Now, $2(6y-8)+5y=1$ This gives: $12y-16+5y=1$ or, $y=1$ Thus, $x=6(1)-8=-2$ Solution is: $(x,y)=(-2,1)$