Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 7 - Section 7.1 - Systems of Linear Equations in Two Variables - Exercise Set - Page 818: 24

Answer

The required value is $x=-6,y=-2$

Work Step by Step

We have to multiply the second equation with 7 and add it to the first equation: $\begin{align} & 2x-7y+7\left( 3x+y \right)=2+7\left( -20 \right) \\ & 2x-7y+21x+7y=2-140 \\ & 23x=-138 \\ & x=-6 \end{align}$ Substitute the value of $x=-6$ in the first equation: $\begin{align} & 2\left( -6 \right)-7y=2 \\ & -12-7y=2 \\ & -7y=14 \\ & y=-2 \end{align}$
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