Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 7 - Section 7.1 - Systems of Linear Equations in Two Variables - Exercise Set - Page 818: 13



Work Step by Step

Here, we have $3x= 11+y \implies y=3x-11$ Now, $2x+5(3x-11)=-4$ This gives: $17 x=51 $ or, $x=3$ Thus, $y=3(3)-11=-2$ Solution is: $(x,y)=(3,-2)$
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