## Precalculus (6th Edition) Blitzer

Published by Pearson

# Chapter 7 - Section 7.1 - Systems of Linear Equations in Two Variables - Exercise Set - Page 818: 18

#### Answer

$\left\{ \left( -4,4 \right) \right\}$ Is the solution of the system of equations.

#### Work Step by Step

Step 1: And solve for y in the second equation to obtain the value of y in terms of x: Since, $y=\frac{3}{4}x+7$ Step 2: Put $y=\frac{3}{4}x+7$ in the first equation to obtain the value of x: \begin{align} & \frac{3}{4}x+7=-\frac{1}{2}x+2 \\ & \frac{3}{4}x+\frac{1}{2}x=2-7 \\ & \frac{5}{4}x=-5 \\ & x=-4 \end{align} Step 3: Now, put the value, $x=-4$ in the second equation to obtain the value of y: \begin{align} & y=\frac{3}{4}\left( -4 \right)+7 \\ & =-3+7 \\ & =4 \end{align} Thus, the solution set $\left( x,y \right)$ to the system of equation is $\left\{ \left( -4,4 \right) \right\}$.

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