Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 7 - Section 7.1 - Systems of Linear Equations in Two Variables - Exercise Set - Page 818: 22


The required value is $x=4,y=1$

Work Step by Step

We add both equations to obtain, $\begin{align} & \left( 3x+2y \right)+\left( 3x-2y \right)=14+10 \\ & 3x+3x+2y-2y=24 \\ & 6x=4 \\ & x=4 \end{align}$ Substitute the value of $x=4$ in the first equation to obtain, $\begin{align} & 3\left( 4 \right)+2y=14 \\ & 12+2y=14 \\ & 2y=2 \\ & y=1 \end{align}$ Thus, the value of $x=4$ and $y=1$.
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