Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 4 - Section 4.8 - Applications of Trigonometric Functions - Exercise Set - Page 637: 8

Answer

$ b=64.84;A=9.8^{\circ}; B=80.2^{\circ}$

Work Step by Step

The trigonometric ratios are as follows: $\sin \theta= \dfrac{opposite}{hypotenuse}$ ; $\cos \theta= \dfrac{Adjacent}{hypotenuse}$ and $\tan \theta= \dfrac{Opposite}{Adjacent}$ $\sin A=\dfrac{11.2}{65.8}=0.1702$ $\implies A=9.8^{\circ}$ So, $ B=90^{\circ}- 9.8^{\circ}=80.2^{\circ}$ Thus, $ b=64.84;A=9.8^{\circ}; B=80.2^{\circ}$
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