Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 4 - Section 4.8 - Applications of Trigonometric Functions - Exercise Set - Page 637: 1


$ a=4.35; c=10.9; B=66.5^{\circ}$

Work Step by Step

Here, we have $ A= 23.5^{\circ}$ ; $ b= 10$ Since, $\tan \theta= \dfrac{Opposite}{Adjacent}$ $ a= b \tan A =10 \tan 23.5^{\circ} =4.35$ Now, $ c=\dfrac{b}{\cos A}=\dfrac{10}{\cos 23.5^{\circ}}=10.9$ So, $ B=90^{\circ} -23.5^{\circ}=66.5^{\circ}$ Thus, $ a=4.35; c=10.9; B=66.5^{\circ}$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.